Discussion
Which of these expressions gives the torque developed at a slip \( s \), for a rotor emf \( E_2 \)?
Answer: D
Correct answer: \( sE_2^2R_2/(R_2^2 + s^2X_2^2) \)
At slip \( s \) the rotor emf is \( sE_2 \) and the rotor reactance \( sX_2 \), so the current is \( sE_2/\sqrt{R_2^2 + s^2X_2^2} \). Torque is proportional to \( I_2^2 R_2/s \), and substituting gives the expression above. It has the familiar shape: rising nearly linearly from zero slip, peaking, then falling away.
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