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At small slip the torque of an induction machine is approximately proportional to

  • A.the slip itself
  • B.the inverse of the slip
  • C.the square of the slip
  • D.the square root of the slip

Answer: A

Correct answer: the slip itself

At small slip \( s^2X_2^2 \) is negligible beside \( R_2^2 \), and the torque expression reduces to \( sE_2^2/R_2 \). This is why the speed of a loaded induction machine falls almost linearly with torque over the working range, and why the machine behaves as a nearly constant speed drive.

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