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An induction machine takes 30 kW from its supply, with 1.2 kW of stator copper loss and 0.8 kW of core loss. Its air gap power is

  • A.32 kW
  • B.2 kW
  • C.28 kW
  • D.30 kW

Answer: C

Correct answer: 28 kW

Air gap power is what remains of the input after the losses in the stator: \[ 30 - 1.2 - 0.8 = 28\ \mathrm{kW}. \] Everything that crosses the air gap is then divided between the rotor copper loss and the mechanical power, in the ratio \( s \) to \( 1-s \).

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