Discussion
A maize sheller processes \( 900 \) kg of cobs yielding \( 720 \) kg of kernels. The shelling percentage is
Answer: C
Correct answer: 80.0 per cent
The shelling percentage is the kernel mass as a fraction of the cob mass fed:
\[ \frac{720}{900} \times 100 = 80.0\ \mathrm{per\ cent} \]
The remaining 20 per cent is the cob itself, which is discarded or used as fuel. The figure is a property of the crop more than of the machine - variety, maturity and moisture all affect it - so it is used as a check on the crop rather than as a measure of how well the sheller is performing.
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