Discussion
Surendra travels from home to office by car. With an average speed of 50 km/hr, he is late by 30 minutes. But when he comes with a speed of 60 km/h, he reaches his office 10 minutes earlier. How far is his office from his home?
Answer: C
One trip is 30 minutes late and the other 10 minutes early, so the travel times differ by 40 minutes.
\[ \frac{D}{50} - \frac{D}{60} = \frac{40}{60} = \frac{2}{3} \text{ h} \]
\[ D\left(\frac{6 - 5}{300}\right) = \frac{2}{3} \quad\Longrightarrow\quad \frac{D}{300} = \frac{2}{3} \]
\[ D = 200 \text{ km} \]
Late and early must be added to get the gap: 30 + 10 = 40 minutes, not their difference.
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