Discussion
Ramesh sees a thief at a distance of 80 m. Ramesh starts chasing the thief who is running at a speed of 5 m/s. Ramesh is chasing him with a speed of 7 m/s. How much distance does the thief covers before Ramesh catches him?
Answer: D
The gap closes at the difference of the two speeds.
\[ \text{relative speed} = 7 - 5 = 2 \text{ m/s} \]
\[ t = \frac{80}{2} = 40 \text{ s} \]
\[ \text{thief's distance} = 5 \times 40 = 200 \text{ m} \]
Ramesh covers 280 m in the same time - exactly 80 m more, which is the head start he had to make up. The question asks for the thief's distance, not Ramesh's.
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