Discussion
A boy has to cover a total distance of 300 kms. in 6 hours. He travels at the rate of 60 kmph. for first 90 minutes and next 100 kms. at the rate of 50 kmph. At what average speed must he travel now in order to complete the journey in 6 hours?
Answer: C
Track distance and time together.
\[ \text{first stage} = 60 \times 1.5 = 90 \text{ km in } 1.5 \text{ h} \]
\[ \text{second stage} = \frac{100}{50} = 2 \text{ h for } 100 \text{ km} \]
\[ \text{covered} = 190 \text{ km in } 3.5 \text{ h} \]
\[ \text{remaining} = 110 \text{ km in } 2.5 \text{ h} \quad\Longrightarrow\quad \frac{110}{2.5} = 44 \text{ kmph} \]
The 90 minutes must become 1.5 hours before it can be combined with the rest.
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