Discussion
If John covers a certain distance in 1 hr. 24 min. by covering two third of the distance at 4 kmph and the rest at 5 kmph, then find the total distance.
Answer: B
Let the total distance be \( D \). The two legs take
\[ \frac{2D/3}{4} + \frac{D/3}{5} = 1 \text{ h } 24 \text{ min} = 1.4 \text{ h} \]
\[ \frac{D}{6} + \frac{D}{15} = \frac{5D + 2D}{30} = \frac{7D}{30} \]
\[ \frac{7D}{30} = 1.4 \quad\Longrightarrow\quad D = 6 \text{ km} \]
Checking: 4 km at 4 kmph is 1 hour and 2 km at 5 kmph is 24 minutes.
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