Discussion
How much time does a train 125 metres long running at 60 km/hr take to pass a pole?
Answer: C
A pole has no length, so the train covers only its own length in passing it.
\[ 60 \text{ km/hr} = 60 \times \frac{5}{18} = \frac{50}{3} \text{ m/s} \]
\[ t = \frac{125}{50/3} = \frac{375}{50} = 7.5 \text{ s} \]
Passing a platform would require adding the platform's length; a pole adds nothing.
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