Discussion
Sourav walks 20 meters towards North. He then turns left and walks 40 meters. He again turns left and walks 20 meters. Further, he moves 20 meters after turning to
right. How far is he from his original position?
Answer: D
Track the two axes separately. Starting north, a left turn faces west, another left faces south, then a right turn faces west again.
- 20 m north
- 40 m west
- 20 m south
- 20 m west
\[ \text{north--south} = 20 - 20 = 0 \]
\[ \text{east--west} = 40 + 20 = 60 \text{ m west} \]
The vertical movements cancel exactly, so the displacement is a straight 60 metres - no Pythagoras needed.
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