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A train can travel 50% faster than a car. Both start from point A at the same time and reach point B, 75 km away from A, at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:

  • A.100 kmph
  • B.110 kmph
  • C.120 kmph
  • D.130 kmph

Answer: C

Let the car do \( c \) kmph; the train then does \( 1.5c \). Both leave together and arrive together, but the train idles 12.5 minutes.

\[ \frac{75}{c} = \frac{75}{1.5c} + \frac{12.5}{60} \]

\[ \frac{75}{c} - \frac{50}{c} = 0.20833 \quad\Longrightarrow\quad \frac{25}{c} = 0.20833 \]

\[ c = 120 \text{ kmph} \]

Checking: the car takes 37.5 minutes and the train 25 minutes of running plus 12.5 minutes stopped - both 37.5 in total.

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