Discussion
A man leaves a point P at 6 a.m. and reaches the point Q at 10 a.m. another man leaves the point give at 8 a.m. and reaches the point P at 12 noon. At what time do they meet?
Answer: C
Each man takes four hours, so their speeds are equal - call each \( \tfrac{d}{4} \).
By 8 a.m. the first has already covered half the distance:
\[ 2 \times \frac{d}{4} = \frac{d}{2} \]
The gap is then \( \tfrac{d}{2} \), closing at their combined speed \( \tfrac{d}{2} \) per hour:
\[ t = \frac{d/2}{d/2} = 1 \text{ hour} \]
So they meet at 9 a.m. The distance cancels, so it never needs a value.
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