Discussion
A 180 meter long train crosses a man standing on the platform in 6 sec. What is the speed of the train?
Answer: B
A man standing is a point, so the train covers only its own length.
\[ v = \frac{180}{6} = 30 \text{ m/s} \]
\[ 30 \times \frac{18}{5} = 108 \text{ kmph} \]
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