Discussion
A train leaves Delhi at 9 a.m. at a speed of 30 kmph. Another train leaves at 2 p.m. at a speed of 40 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet?
Answer: C
The first train leaves five hours earlier, so it is
\[ 30 \times 5 = 150 \text{ km} \]
ahead at 2 p.m. The gap closes at \( 40 - 30 = 10 \) kmph:
\[ t = \frac{150}{10} = 15 \text{ hours} \]
\[ \text{distance from Delhi} = 40 \times 15 = 600 \text{ km} \]
Checking with the first train: \( 30 \times 20 = 600 \) km in the twenty hours since 9 a.m.
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