Discussion
A train 150 m long running at 72 kmph crosses a platform in 25 sec. What is the length of the platform?
Answer: C
\[ 1 \text{ kmph} = \frac{5}{18} \text{ m/s} \]
\[ 72 \text{ kmph} = 20 \text{ m/s} \]
\[ \text{total distance} = 20 \times 25 = 500 \text{ m} \]
\[ \text{platform} = 500 - 150 = 350 \text{ m} \]
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