Discussion
In how much time will a train of length 100 m, moving at 36 kmph cross an electric pole?
Answer: D
\[ 1 \text{ kmph} = \frac{5}{18} \text{ m/s} \]
\[ 36 \text{ kmph} = 10 \text{ m/s} \]
An electric pole has no length, so the train covers only its own 100 m:
\[ t = \frac{100}{10} = 10 \text{ sec} \]
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