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Two trains are moving in the same direction at 72 kmph and 36 kmph. The faster train crosses a man in the slower train in 27 seconds. Find the length of the faster train?

  • A.270 m
  • B.250 m
  • C.280 m
  • D.220 m

Answer: A

Trains in the same direction close at the difference of their speeds; in opposite directions, at the sum.

\[ 1 \text{ kmph} = \frac{5}{18} \text{ m/s} \]

Crossing a man in the other train covers only the faster train's length.

\[ \text{relative speed} = 72 - 36 = 36 \text{ kmph} = 10 \text{ m/s} \]

\[ L = 10 \times 27 = 270 \text{ m} \]

The slower train's own length is irrelevant, since the reference point is a single person.

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