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A bus travels at a speed of 50 km/h for 12 minutes & then at a speed of 40 km/h for the next 18 minutes. Total distance covered by the bus during this time is –

  • A.20 km
  • B.22 km
  • C.24 km
  • D.28 km

Answer: B

The total distance is 22 km.

Distance = speed × time, with the time converted to hours:

\[ \begin{aligned} d_{1} &= 50 \times \frac{12}{60} = 10\ \text{km} \\ d_{2} &= 40 \times \frac{18}{60} = 12\ \text{km} \\ d &= 10 + 12 = 22\ \text{km} \end{aligned} \]

Averaging the two speeds (45 km/h) over the 30 minutes gives 22.5 km, which is wrong because the bus spends different times at each speed. Swapping the two times gives 15 + 8 = 23 km, and 20, 24 and 28 km do not follow from distance = speed × time with the times given.

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