Discussion
A man on tour travels first 160 km at 54 km/hr and the next 160 km at 76 km/hr. The average speed for the first 320 km of the tour is.
Answer: B
The average speed is 63.14 km/hr. The average speed is the total distance divided by the total time, and not the mean of the two speeds. The time for the first 160 km is \(\frac{160}{54} = 2.963\) hours and for the next 160 km is \(\frac{160}{76} = 2.105\) hours. \[ \text{Average} = \frac{320}{2.963 + 2.105} \] \[ \frac{320}{5.068} \approx 63.14 \] The mean of 54 and 76 is 65, which is not an option, and the average must lie between the two speeds and nearer the lower one, since more time is spent at 54 km/hr, so 76.14 and 49.14 lie outside the two speeds and 73.14 is too close to the higher one.
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