Discussion
Let P and Q starts simultaneously from a certain point in East and West direction on a cycle. Speed of P is 90 km/hr and that of Q is 75 km/hr. What is distance between P and Q after 15 minutes?
Answer: B
P and Q start from the same point and go in opposite directions, east and west, so the distance between them grows at the sum of their speeds.
\[ 90 + 75 = 165\ \text{km/hr} \]
The time is 15 minutes, which is a quarter of an hour.
\[ d = 165 \times \frac{1}{4} = 41.25\ \text{km} \]
The values 41, 41.50 and 42.25 differ from the product by small amounts and are traps for a slip in the division. The answer is 41.25 km, option B.
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