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A thief started running from point X at a speed of 20 km/h. After running for 30 minutes, when he watched the policeman at the distance of 400 m coming in from the opposite direction at the speed of 30 km/h, he turned and started running at 25 km/h in the same direction as the policeman. After how much distance from point X, will the policeman catch the thief?

  • A.11 km
  • B.9 km
  • C.10 km
  • D.8 km

Answer: D

The policeman catches the thief 8 km from X. In 30 minutes at 20 km/h the thief has run 10 km from X. The policeman is 0.4 km further on, coming towards him at 30 km/h. The thief turns and runs the same way as the policeman at 25 km/h, so the gap of 0.4 km closes at 30 - 25 = 5 km/h. The time taken is 0.4/5 = 0.08 hour. In that time the thief runs 25 x 0.08 = 2 km back towards X, so the catch happens 10 - 2 = 8 km from X. The options 11, 9 and 10 km do not follow from this closing speed.

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