Discussion
A meeting is scheduled at 11:00 AM and a person 'P', who is at a distance of 100 km from the meeting place, has to attend. If 'P' starts at 09:45 AM in his car which moves with a speed of 60 kmph, then 'P' is late to the meeting by how many minutes ?
Answer: C
P is late by 25 minutes.
The time needed to cover 100 km at 60 km/h is
\[ \begin{aligned} t &= \frac{100}{60}\ \text{h} = 1\frac{2}{3}\ \text{h} \\ &= 1\ \text{h}\ 40\ \text{min} \end{aligned} \]
Starting at 9:45 AM, P arrives at 11:25 AM, which is 25 minutes after the 11:00 AM start. 15 minutes is what you get by taking 100 km at 60 km/h as one and a half hours, and 5 or 35 minutes come from errors in converting the fraction of an hour into minutes.
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