Discussion
If a tiger is 50 of its own leaps behind a deer. The tiger takes 5 leaps per minutes to deer's 4. If the tiger and deer cover 8 m and 5 m per leap respectively, what distance will the tiger have to run before it catches the deer?
Answer: B
The tiger must run 800 m.
Convert leaps to metres. The tiger covers \(5 \times 8 = 40\) m per minute and the deer \(4 \times 5 = 20\) m per minute. The gap is 50 tiger leaps:
\[ \begin{aligned} \text{gap} &= 50 \times 8 = 400\ \text{m} \\ \text{time} &= \frac{400}{40 - 20} = 20\ \text{min} \\ \text{distance} &= 40 \times 20 = 800\ \text{m} \end{aligned} \]
400 m is the gap, not the distance run. 1000 m would come from a 25-minute chase, and 600 m and 700 m do not match the closing speed of 20 m per minute.
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