Discussion
A conductor of length \( l \) moving with velocity \( v \) at right angles to a field \( B \) develops an emf of
Answer: C
The expression follows from integrating \( \mathbf{v} \times \mathbf{B} \) along the conductor when all three vectors are mutually perpendicular. If the motion is not perpendicular to the field the component of velocity along the field contributes nothing.
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