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A capacitor of 1 \( \mu \)F carries an alternating voltage rising at \( 10^{6} \) V/s. The displacement current through its dielectric is

  • A.zero
  • B.1 A
  • C.1 \( \mu \)A
  • D.1 mA

Answer: B

The current is the capacitance times the rate of change of voltage, that is \( 10^{-6} \times 10^{6} = 1 \) A. It is carried entirely by the changing electric flux, no charge crossing the dielectric at all, which is the whole point of the displacement term.

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