Discussion
A transformer's secondary of 500 turns links a sinusoidal flux of 2 mWb peak at 50 Hz. The rms emf is about
Answer: C
The standard transformer equation is \( 4.44 f N \Phi_m \), which gives \( 4.44 \times 50 \times 500 \times 2 \times 10^{-3} = 222 \) V. The coefficient is \( 2\pi/\sqrt{2} \), combining the differentiation with the conversion to rms.
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