Discussion
Rakesh is twice as efficient as Shalini. If he can finish a piece of work in 25 days less than Shalini, then how many days does Shalini require to complete the same work?
Answer: C
Shalini needs 50 days.
Rakesh is twice as efficient, so he takes half of Shalini's time. If Shalini takes S days, Rakesh takes S/2 days, and the difference is 25 days.
\[ S-\frac{S}{2}=25 \Rightarrow S=50 \]
35, 45 and 60 do not satisfy this condition.
The check is easy: if Shalini takes 50 days, Rakesh takes half of that, 25 days, and 50 − 25 = 25 days less, as stated. Twice the efficiency always means half the time for the same work.
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