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The polar second moment of area of a solid circular shaft of diameter d is

  • A.Pi d squared, over four
  • B.Pi d to the fourth, over thirty-two
  • C.Pi d to the fourth, over sixty-four
  • D.Pi d cubed, over sixteen

Answer: B

The polar value is twice the diametral second moment of area, so where the diametral figure carries sixty-four in the denominator the polar one carries thirty-two. The value over sixteen is the polar section modulus rather than the second moment.

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