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A member of length \( 3 \) m carries \( 5 \) kN m with \( GJ = 1.5 \times 10^6 \) N m\( ^2 \). Its total twist is nearest to

  • A.0.57 degrees
  • B.0.01 degrees
  • C.1.15 degrees
  • D.0.19 degrees

Answer: A

Correct answer: 0.57 degrees

\[ \theta = \frac{TL}{GJ} = \frac{5000 \times 3}{1.5 \times 10^6} = 0.01\ \text{radians}, \] which converted gives \[ 0.01 \times \frac{180}{\pi} = 0.57\ \text{degrees}. \] The option offering 0.01 degrees is the trap: it is the answer in radians presented as though it were degrees.

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