Discussion
A torsion box of enclosed area \( 1.2 \) m\( ^2 \) and uniform \( 2.5 \) mm wall has a perimeter of \( 4.4 \) m. Its torsion constant is nearest to
Answer: C
Correct answer: 3.27e-3 m^4
Bredt’s formula gives \[ J = \frac{4A^2t}{s} = \frac{4(1.2)^2(0.0025)}{4.4} \] \[ = \frac{0.0144}{4.4} = 3.27 \times 10^{-3}\ \mathrm{m^4}. \] The enclosed area appears squared and the thickness only to the first power, which is why a wing box gains far more torsional stiffness from depth and chord than from skin gauge.
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