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An LVDT of sensitivity 20 mV per mm shows an output of 250 mV. The core displacement is

  • A.0.08 mm
  • B.12.5 mm
  • C.5 mm
  • D.5000 mm

Answer: B

Correct answer: 12.5 mm

\[ \frac{250\ \mathrm{mV}}{20\ \mathrm{mV/mm}} = 12.5\ \mathrm{mm}. \] Dividing by the sensitivity converts output back to input; multiplying instead gives 5000 mm, which is offered here. The sign of the displacement is not recoverable from magnitude alone, which is why an LVDT is used with phase-sensitive detection.

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