Discussion
A capacitive transducer has plates of 100 mm\( ^2 \) separated by 1 mm of air. Taking \( \epsilon_0 = 8.85 \) pF/m, its capacitance is about
Answer: D
From \( C = \epsilon_0 A/d \), with \( A = 10^{-4} \) m² and \( d = 10^{-3} \) m, the capacitance is \( 8.85 \times 10^{-12} \times 10^{-1} = 0.885 \) pF. Such a small value shows why stray capacitance is the dominant practical difficulty.
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