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An accelerometer of sensitivity 10 pC per g is used with a charge amplifier of 1 mV per pC. An acceleration of 5 g gives an output of

  • A.500 mV
  • B.2 mV
  • C.50 mV
  • D.10 mV

Answer: C

The charge is \( 10 \times 5 = 50 \) pC and the amplifier turns each picocoulomb into a millivolt, so the output is 50 mV. The cable capacitance does not enter, which is the whole reason for using a charge amplifier rather than a voltage one.

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