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Parallel blocks with transfer functions \(G_1(s)\) and \(G_2(s)\) can be replaced by a single block with transfer function equal to ______.

  • A.\(G_1(s) + G_2(s)\)
  • B.\(G_1(s)G_2(s)\)
  • C.\(\dfrac{G_1(s)}{G_2(s)}\)
  • D.\(\dfrac{G_1(s)G_2(s)}{G_1(s) + G_2(s)}\)

Answer: A

When two blocks are in parallel, they receive the same input and their outputs are added at a summing point, so the overall transfer function is the sum.


\[ G(s) = G_1(s) + G_2(s) \]


The product \(G_1(s)G_2(s)\) is the result for blocks in cascade (series). The ratio \(G_1/G_2\) does not correspond to any simple connection, and \(\dfrac{G_1 G_2}{G_1 + G_2}\) is the form of two resistors in parallel, not of transfer functions in parallel. The answer is option A.

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