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That transformer supplying 20 A on its secondary draws a primary current of about

  • A.20 A
  • B.100 A
  • C.5 A
  • D.80 A

Answer: C

Correct answer: 5 A

Ampere-turns balance, so the current transforms by the inverse of the turns ratio: \[ I_1 = I_2\frac{N_2}{N_1} = 20 \times \frac{250}{1000} = 5\ \text{A.} \] Check it against the power: the secondary delivers \( 100 \times 20 = 2000 \) VA and the primary draws \( 400 \times 5 = 2000 \) VA, as it must if losses are neglected.

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