Discussion
A load impedance of 4 Ω on the secondary of that transformer appears at the primary as
Answer: D
Correct answer: 64 Ω
Impedance transforms by the square of the turns ratio: \[ Z_1 = \left(\frac{N_1}{N_2}\right)^2 Z_2 = 4^2 \times 4 = 64\ \Omega. \] Forgetting the square gives 16, which is one of the distractors. A step-down transformer therefore makes a low impedance look large from the primary side, which is precisely what impedance matching exploits.
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