Discussion
In a single-phase transformer, the ratio of transformation is 2 and the secondary resistance is \(0.48\ \Omega\). Find the resistance of secondary in terms of primary.
Answer: A
A resistance on the secondary side is referred to the primary side by dividing by the square of the turns ratio. The ratio of transformation is \(K = 2\).
\[ \begin{aligned} R_2' = \frac{R_2}{K^2} = \frac{0.48}{2^2} \\ &= \frac{0.48}{4} = 0.12\ \Omega \end{aligned} \]
The value 0.24 ohm comes from dividing by \(K\) instead of \(K^2\), and 0.06 ohm from dividing by \(2K^2\). The value 0.18 has no basis. The answer is 0.12 ohm, option A.
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