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A 25 KVA transformer has a voltage ratio of 3300/400 V. Calculate the Primary and Secondary Currents:

  • A.16 A, 132 A
  • B.7.58 A, 62.5 A
  • C.13.2 A, 160 A
  • D.6.25 A, 75.8 A

Answer: B

The currents are 7.58 A, 62.5 A.

For a single-phase transformer, current is the rating divided by the voltage on each side:

\[ \begin{aligned} I_{1} &= \frac{25000}{3300} \approx 7.58\ \text{A} \\ I_{2} &= \frac{25000}{400} = 62.5\ \text{A} \end{aligned} \]

As a check, the currents are in the inverse ratio of the voltages: \(62.5/7.58 \approx 8.25 = 3300/400\).

6.25 A, 75.8 A reuses the same digits, but neither value is 25 kVA divided by 3300 V or by 400 V; 16 A, 132 A and 13.2 A, 160 A do not come from these figures either.

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