Discussion
The no-load current of a transformer is-
Answer: B
The no-load current is the phasor sum of \(I_{m}\) and \(I_{c}\).
On no load the primary draws a small current \(I_{0}\) with two components at right angles: the magnetising current \(I_{m}\), in phase with the flux and lagging the voltage by 90°, which sets up the flux; and the core loss component \(I_{c}\), in phase with the voltage, which supplies the iron loss. Since they are 90° apart they add as phasors: \(I_{0} = \sqrt{I_{m}^{2} + I_{c}^{2}}\).
Adding them algebraically ignores the 90° between them. \(I_{0}\) is itself the no-load current, and \(I_{1}\) is the primary current under load, so options built from them are wrong.
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