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Paramagnetic transition metal ion is:

  • A.\(\mathrm{Ti^{4+}}\)
  • B.\(\mathrm{V^{4+}}\)
  • C.\(\mathrm{Zn^{2+}}\)
  • D.\(\mathrm{Cu^{+}}\)

Answer: B

A transition metal ion is paramagnetic if it has unpaired d electrons. Count the d electrons of each ion.


\[ \begin{aligned} \mathrm{Ti^{4+}}: d^0,\quad \mathrm{V^{4+}}: d^1 \\ \mathrm{Zn^{2+}}: d^{10},\quad \mathrm{Cu^{+}}: d^{10} \end{aligned} \]


\(\mathrm{V^{4+}}\) (vanadium, atomic number 23, loses four electrons) has one electron in the 3d subshell, which is unpaired, so it is paramagnetic. \(\mathrm{Ti^{4+}}\) has an empty d subshell, and \(\mathrm{Zn^{2+}}\) and \(\mathrm{Cu^{+}}\) have filled d subshells, so they have no unpaired electrons and are diamagnetic. The answer is option B.

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