Discussion
Paramagnetic transition metal ion is:
Answer: B
A transition metal ion is paramagnetic if it has unpaired d electrons. Count the d electrons of each ion.
\[ \begin{aligned} \mathrm{Ti^{4+}}: d^0,\quad \mathrm{V^{4+}}: d^1 \\ \mathrm{Zn^{2+}}: d^{10},\quad \mathrm{Cu^{+}}: d^{10} \end{aligned} \]
\(\mathrm{V^{4+}}\) (vanadium, atomic number 23, loses four electrons) has one electron in the 3d subshell, which is unpaired, so it is paramagnetic. \(\mathrm{Ti^{4+}}\) has an empty d subshell, and \(\mathrm{Zn^{2+}}\) and \(\mathrm{Cu^{+}}\) have filled d subshells, so they have no unpaired electrons and are diamagnetic. The answer is option B.
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development