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The order of values of spin only magnetic moment is

  • A.III \(\gt\) II \(\gt\) I
  • B.III \(\gt\) I \(\gt\) II
  • C.II \(\gt\) I \(\gt\) III
  • D.I \(\gt\) II \(\gt\) III

Answer: D

The order of spin-only magnetic moments is I \(\gt\) II \(\gt\) III.

Chloride is a weak-field ligand and tetrahedral splitting is small, so all three complexes are high spin. Count the unpaired d electrons:

  • [FeCl4]2-: Fe2+, d6, 4 unpaired, \(\mu = \sqrt{24} = 4.90\) BM
  • [CoCl4]2-: Co2+, d7, 3 unpaired, \(\mu = \sqrt{15} = 3.87\) BM
  • [NiCl4]2-: Ni2+, d8, 2 unpaired, \(\mu = \sqrt{8} = 2.83\) BM

using \(\mu = \sqrt{n(n + 2)}\). The moment falls as electrons are added beyond d5, so every order putting III or II first is reversed.

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