Discussion
If a triangle ABC is right angled at C, then the value of \(\cos(A+B)\) is:
Answer: A
In a triangle the angles add to 180°, and \( C = 90^{\circ} \), so
\[ A + B = 90^{\circ} \]
\[ \cos(A+B) = \cos 90^{\circ} = 0 \]
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