Discussion
The value of \(\frac{\sin 18°}{\cos 72°}\) is:
Answer: B
Use the complementary-angle identity \( \cos(90^{\circ} - \theta) = \sin\theta \).
\[ \cos 72^{\circ} = \cos(90^{\circ} - 18^{\circ}) = \sin 18^{\circ} \]
\[ \frac{\sin 18^{\circ}}{\sin 18^{\circ}} = 1 \]
Neither value has to be computed - only recognised as equal.
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