Discussion
A ramp for a wheelchair has an angle of elevation of 5°. If the ramp is 12 feet long, how high off the ground is the top of the ramp? (Given sin 5° ≈ 0.087)
Answer: B
Let h be the height and L be the length of the ramp.
\(\sin(\text{angle}) = \frac{\text{height}}{\text{length}}\)
\(\sin 5° = \frac{h}{12}\)
h = 12 × \(\sin 5°\) ≈ 12 × 0.087 = 1.044 feet.
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