Discussion
2 successive discounts with the first being 20%, were given on a table having marked price of Rs. 6400. Finally it was sold for Rs. 4608. How much was the 2nd discount?
Answer: B
Apply the first discount, then find what fraction of that remains.
\[ 6400 \times (1 - 0.20) = \text{Rs. } 5120 \]
\[ \frac{4608}{5120} = 0.90 \quad\Longrightarrow\quad \text{second discount} = 10\% \]
Checking: \( 5120 \times 0.90 = 4608 \).
The overall reduction is \( \dfrac{6400 - 4608}{6400} = 28\% \), which matches \( 1 - 0.80 \times 0.90 \) - but 28% is the combined figure, not the second discount.
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