Discussion
A turboprop delivers \( 2500 \ \mathrm{N\,m} \) at \( 1600 \ \mathrm{rpm} \) at the propeller shaft. The shaft power is approximately
Answer: A
Angular speed is \( 1600 \times 2\pi/60 = 167.6 \) radians per second, so the power is \( 2500 \times 167.6 \approx 419 \) kilowatts. With rpm governed constant, torque alone then tracks power, which is why it serves as the power setting parameter.
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