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The dimensional formula for the product of moment of inertia and the square of angular velocity is

  • A.\(MLT^{-2}\)
  • B.\(ML^{2}T^{-1}\)
  • C.\(ML^{0}T^{-2}\)
  • D.\(ML^{2}T^{-2}\)
  • E.\(MLT^{-1}\)

Answer: D

The dimensional formula is \(ML^{2}T^{-2}\).

Moment of inertia is mass times distance squared, \([ML^{2}]\), and angular velocity is per unit time, \([T^{-1}]\):

\[ [I\omega^{2}] = [ML^{2}][T^{-2}] = [ML^{2}T^{-2}] \]

This is the dimension of energy, as expected, since rotational kinetic energy is \(\frac{1}{2}I\omega^{2}\). \(ML^{2}T^{-1}\) is angular momentum \(I\omega\), \(MLT^{-2}\) is force, \(MLT^{-1}\) is linear momentum, and \(ML^{0}T^{-2}\) drops the length dimension.

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