Discussion
A reading of \( 0.80 \) corresponds to a transmittance of about
Answer: A
Inverting the logarithmic definition:
\[ T = 10^{-0.80} \approx 0.158 \]
giving about 16 per cent. Eighty per cent confuses the absorbance's numerical value with a percentage, which the logarithm makes impossible. Since each unit of absorbance is a tenfold reduction, a reading of 0.8 lets through rather less than a fifth of the light.
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