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Why can a diode array instrument damage photosensitive samples?

  • A.The sample sees the full undispersed beam
  • B.The array requires a more intense source
  • C.The measurement takes longer than a scan
  • D.The sample is heated by the detector array

Answer: A

Because dispersion happens after the sample, the whole output of the lamp passes through the solution rather than one narrow band at a time. The source is comparable, the measurement is far quicker, and the detector is nowhere near the sample. Reversing the order of two components to gain speed has moved a stress onto the sample, which is a consequence worth anticipating before a photolabile compound is put in one. The shared properties explain why these belong to one family, and the differences explain why more than one exists.

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