Discussion
The net workdone in the cycle is approximately
Answer: C
The net work is about 1204 kJ/kg.
Find the low-pressure turbine exit enthalpy from the quality, using \(h_{f} = h_{1}\) at 10 kPa:
\[ \begin{aligned} h_{6} &= 191.81 + 0.92285(2584.63 - 191.81) = 2400.0 \\ w_{T} &= (h_{3} - h_{4}) + (h_{5} - h_{6}) \\ &= 339.22 + 867.95 = 1207.2 \\ w_{net} &= 1207.2 - 3.02 = 1204.2\ \text{kJ/kg} \end{aligned} \]
The pump work, 3.02 kJ/kg, is small but subtracted. As a check, the cycle efficiency is 1204/3412, about 35 percent, a sensible figure. The other options do not follow from the given enthalpies.
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